You are referencing the variables properly on the first if line, but then
you're calling $var1 and $var2 w/o using $_GET. Add that or do this:
$var1 = $_GET['var1'];
$var2 = $_GET['var2'];
You may also want to use !isset($varname) instead of checking to see if
the variables are equal to a space char (" ").
-Dash
"I have made mistakes but I have never made the mistake of claiming
that I have never made one."
-- James Gordon Bennett
On Wed, 29 Jan 2003, Wade wrote:
> 01292003 1540 CST
>
> When I run this script I get the html at the end but no $result. If the
> result is run on the same page as the output, there shouldnt be anything
> variable wise stopping this from running, right?
>
> Wade
>
> <?php
> if (($_POST["val1"] == " ") || ($_POST["val2"] == " ") ||
> ($_POST["calc"] == " "))
> {
> header("Location: http://localhost/Learning PHP/PHP Fast &
> Easy/Ch_6/calculate_form.html");
> exit;
> }
>
> if ($_POST["calc"] == "add")
> {
> $result = $val1 + $val2;
> }
>
> else if ($_POST["calc"] == "subtract")
> {
> $result = $val1 - $val2;
> }
>
> else if ($_POST["calc"] == "multiply")
> {
> $result = $val1 * $val2;
> }
>
> else if ($_POST["calc"] == "divide")
> {
> $result = $val1 / $val2;
> }
>
> ?>
>
> <html>
> <head>
> <title>Calculation Result</title>
> <head>
>
> <body>
> <p>The result of the calculation is: <?php "$result"; ?></p>
> </body>
> </html>
>
>
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>
>
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