[PHP-WIN] remote URL .jpg

[Anthony Ritter]

Christoph Grottolo wrote in message:

> The manual says that you have to check if creation from url works.
> Maybe you check first if your script works with a local jpg, then if
> you can include a remote url (include ("http://www.nytimes.com";);).

> To send the image you must use:

> <?
> header("Content-type: image/jpeg");
> imagejpeg($thenewimage,'',80);
> imagedestroy($im);
> ?>

> You can not simply echo your image handler ($thenewimage), because
> it's just a resource (pointer) and not a string. To use it you have to
> convert it (back) into a common image format (jpeg, png...)
>
> Additionally you have to send a header in order to tell the browser
> that you're going to send an image (and not a html page).
>
> Just read on in the manual, you know where...
>
> Christoph
...............................................................

Christoph,
I'm not sure what either the arguments that you supplied

like:
''
or
80

is in the function call below.
................................
imagejpeg($thenewimage,'',80);
...............................

Please advise.

Thank you.
TR





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