Hi there,
I want read a directory and open a file inside the directory, for example directory
data contains of file:
Computername.txt
IPaddress.txt
status.txt
and i want search a file on the directory and open it, for example i want search file
IPaddress.txt and when file IPaddress.txt found, i want open it, read and display the
contains of the file.
the script that i have is like this :
<?php
$find_file="name.txt";
if ($handle = opendir('C:\apache\htdocs')){
while (false !== ($file = readdir($handle))){
if ($file == $find_file){
echo " file found $file<br>";
// i want to open the file, but i am confuse with the file handle
$handle_file = fopen ($find_file, "r");
while (!feof ($handle_file)){
$buffer = fgets($handle_file, 4096);
echo "$buffer<br>";
}
}
}
closedir($handle);
}
?>
this script does'nt run correctly i have an error message, "Warning: Supplied argument
is not a valid File-Handle resource in c:\apache\htdocs\fseek\readdir.php on line 11"
I confuse with the file handle, because is different with opening file like usually,
what should i do...??? does any one can help me...??
Thanx
idur
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