--- In [email protected], Pete <[EMAIL PROTECTED]> wrote:
>
> In message <[EMAIL PROTECTED]>, Jim Tyler <[EMAIL PROTECTED]>
> writes
> >So clearly the where clause is not picking up a value from '$_POST
[bird_id]'.
> >I've tried every variant I can think of so the right
> >side of the where clause resolves to a value to no avail. At this
point, nearly
> >any suggestion is welcome.
>
> If the value is not entering your second page - perhaps it isn't
leaving
> the first page.
>
> How about
> <input type=hidden name=bird_id value='$bird_id'>
> just before your submit button.
>
> And I would put a temporary
> echo $edit_bird;
> just before the
> mysql_query($edit_bird,$conn) or die(mysql_error());
> just to be sure what you are getting.
>
> --
> Pete Clark
>
> http://www.hotcosta.com
> http://www.spanishholidaybookings.com
Pete -
Yup - that nailed it. Thank you VERY much. Now all I have to do is
spend some time thinking abut exactly why bird_id, which I still
think SHOULD be defined, is not.
Jim Tyler
The php_mysql group is dedicated to learn more about the PHP/MySQL web database
possibilities through group learning.
Yahoo! Groups Links
<*> To visit your group on the web, go to:
http://groups.yahoo.com/group/php_mysql/
<*> To unsubscribe from this group, send an email to:
[EMAIL PROTECTED]
<*> Your use of Yahoo! Groups is subject to:
http://docs.yahoo.com/info/terms/
