On Sun, Jan 13, 2002 at 10:52:32PM +0100, Gabor Hojtsy wrote :
> > > The question is to check for $_GET [isset($_GET)] or phpversion()
> > > > 4.1.0 [version_compare() is the function for that thing :)].
> > >
> > > Well, you are right, that if we are < 4.1.0, you can do:
> > >
> > > fake.php?_GET[a]=b&_GET[c]=d
> > >
> > > so my idea may not be that good :)
> >
> > Yep ...
> >
> > I'ld like to see a the-all-in-one solution does work < 4.1.0
> > and with >= 4.1.0 without too many restriction. Correction,
> > no 'I' like to see it, but it could be of very valueable
> > benefit for many developers out there.
>
> To correct my statements above, for version compares,
> version_compare() is only available in PHP 4 >= 4.1.0,
> so for these "compatibility snippets", one need to use
> his own version compare function.
For the start, an function_exists() for 'version_compare'
would be a good idea because you definitely know if you
'reached the 4.1.0 boundary' or not.
--
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