ID: 21288 Updated by: [EMAIL PROTECTED] Reported By: empx at gmx dot de -Status: Open +Status: Bogus Bug Type: Documentation problem Operating System: Windows XP SP1 PHP Version: 4.3.0 New Comment:
As explained in bug #20993, this is assumed to be expected behaviour and will unlikely be *fixed* ever. Previous Comments: ------------------------------------------------------------------------ [2004-04-18 04:15:24] php dot devel at homelinkcs dot com > This will be fixed in ZendEngine2. Stay tuned. Downloaded, compiled and tested PHP 5.0.0RC1 and all tests yielded same result as 4.3.4. Example: [EMAIL PROTECTED] php-5.0.0RC1]$ sapi/cli/php <?php print phpversion()."\n"; $a[0] = "original"; $b =& $a[0]; $c = $a; $c[0] = "copy"; print $a[0]."\n"; ?> 5.0.0RC1 copy [EMAIL PROTECTED] php-5.0.0RC1]$ php <?php print phpversion()."\n"; $a[0] = "original"; $b =& $a[0]; $c = $a; $c[0] = "copy"; print $a[0]."\n"; ?> 4.3.4 copy [EMAIL PROTECTED] php-5.0.0RC1]$ ------------------------------------------------------------------------ [2002-12-30 09:39:47] stephan at wanderinghorse dot net Just FYI, i've reproduced this (using the code from the original poster) on PHP 4.2.0 under Linux. ------------------------------------------------------------------------ [2002-12-30 08:57:31] [EMAIL PROTECTED] It seems more explanation should have been needed... This problem is due to misleading behavior of array copies. PHP scripting engine doesn't perform deep-copy on any elements of an array while it copies *the container* of them indeed. This will be fixed in ZendEngine2. Stay tuned. ------------------------------------------------------------------------ [2002-12-30 08:45:08] [EMAIL PROTECTED] Verified. This is yet another "shallow copy" issue. See http://bugs.php.net/20993 ------------------------------------------------------------------------ [2002-12-30 06:52:59] empx at gmx dot de Hello, i have some problems with understanding the following: class Test { var $a; function Test() { $this->a = 0; } function test2() { } } $a[0] = new Test; $b = $a; $a[0]->a = 1; echo($b[0]->a); This outputs 0 as i would expect..but: $a[0] = new Test; $a[0]->test2(); $b = $a; $a[0]->a = 1; echo($b[0]->a); This outputs 1, and i dont understand this, PHP seems to do some sort of referencing here, though i dont want any.. $b[0] = $a[0]; works and creates a real copy, but i was still wondering if $b = $a shouldnt create a copy aswell instead of this referencing stuff... ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=21288&edit=1
