ID: 31927
Updated by: [EMAIL PROTECTED]
Reported By: bart at mediawave dot nl
-Status: Open
+Status: Bogus
Bug Type: Documentation problem
Operating System: WinXP
PHP Version: 5CVS-2005-02-11 (dev)
New Comment:
No bug here.
Previous Comments:
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[2005-02-12 22:32:37] [EMAIL PROTECTED]
Well, probably this should be clarified in the docs.
But the current description looks rather clear to me, though.
Reclassifying as docu problem.
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[2005-02-12 22:22:18] bart at mediawave dot nl
You are right. It isn't a bug. in_array was apparently designed to work
this way and does so properly.
Maybe we should change this to a change/feature request then? Or
otherwise a documentation problem? It simply isn't intuitive for people
now.
This is my last attempt. I won't be re-opening this bug anymore.
------------------------------------------------------------------------
[2005-02-12 14:45:49] [EMAIL PROTECTED]
>An array itself isn't a value.
Nope. Don't know who told you this, but he/she was definitely wrong.
>So, one would expect that in_array checks if all these
>"values" exist in the haystack.
No, see examples in the docs.
No bug here.
------------------------------------------------------------------------
[2005-02-12 01:16:38] bart at mediawave dot nl
The documentation clearly states:
in_array -- Checks if a "value" exists in an array
It doesn't say:
in_array -- Checks if a "variable" exists in an array
An array itself isn't a value. It's a variable containing a collection
of values. So, one would expect that in_array checks if all these
"values" exist in the haystack. (Regardless of the containing variable
type/structure) It shouldn't check if a variable exists in the
haystack.
The exact match behaviour in your example should only happen when the
parameter strict is set. (In my opinion at least)
------------------------------------------------------------------------
[2005-02-11 20:52:14] [EMAIL PROTECTED]
No bug here: in_array() looks for exact match.
This code works fine:
<?php
$a = array(array("NT", "Linux"), array("Irix", "Linux"), "OS2");
if (in_array(array("NT", "Linux"), $a)) {
echo "NT Linux found\n";
}
?>
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the rest of the comments, please view the bug report online at
http://bugs.php.net/31927
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