On Tue, Nov 17, 2009 at 18:31, Daniel Veillard <veill...@redhat.com> wrote: > On Tue, Nov 17, 2009 at 05:03:41PM +0100, Murray Cumming wrote: >> On Tue, 2009-11-17 at 14:24 +0100, Daniel Veillard wrote: >> > On Tue, Nov 17, 2009 at 01:33:44PM +0100, Murray Cumming wrote: >> > > Should I be able to validate an XML document (such as a .glade file) >> > > that has no DOCTYPE line, and therefore doesn't specify a DTD? >> > > >> > > When I try it with xmllint, I get this error >> > > validity error : Validation failed: no DTD found ! >> > > even when I have specified a local DTD with --dtdvalid. >> > >> > Works for me with the version from git head: >> >> Thanks. I was actually using >> xmllint --valid --dtdvalid mydtd.dtd mydoc.xml >> >> So is --dtdvalid an alternative to --valid rather than a way of using >> --valid? > > and alternative, as DTD validation as defined in the XML-1.0 spec > is --valid i.e. validating as parsing based on DOCTYPE contained in > the document, and --dtdvalid is just a different kind of validation > closely related, but certainly different, and in subtle case you may > see different results (but in general it will be the same !) >
I did not know that. This doesn't however seem to be implemented in PHP, Rob... :) Is this something we can implement? Pretty-please? :) AFAICT it could help us _massively_ when rendering "standalone extension" (and possibly per-file) in the documentations. The "root file" (manua.xml) could still have the DTD attached, but when rendering a standalone book (extension/reference) we could simply attach the DTD via "dtdvalid" to get the entities defined in the DTD (all our snippets) and validate it. -Hannes
