Jun 15, 2019, 1:31 PM by jma...@tuta.io: >> The shortest and fastest way is probably: >> : (conc (cons '@) (chop S) '(@)) >> -> (@ "t" "s" "t" @) >> > Basically (cons '(@)(chop S)'(@)) > Neat solution. Thanks! > I mean (conc '(@)(chop S)'(@))
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