On Fri, Mar 18, 2016 at 9:54 PM, Søren Sandmann <soren.sandm...@gmail.com>
wrote:

> On Sun, Mar 6, 2016 at 8:06 PM, <spit...@gmail.com> wrote:
>
>> From: Bill Spitzak <spit...@gmail.com>
>>
>> This removes a high-frequency spike in the middle of some filters that is
>> caused by math errors all being in the same direction.
>>
>> Signed-off-by: Bill Spitzak <spit...@gmail.com>
>> ---
>>  pixman/pixman-filter.c | 12 +++++++++++-
>>  1 file changed, 11 insertions(+), 1 deletion(-)
>>
>> diff --git a/pixman/pixman-filter.c b/pixman/pixman-filter.c
>> index 36dd811..ab62e0a 100644
>> --- a/pixman/pixman-filter.c
>> +++ b/pixman/pixman-filter.c
>> @@ -282,8 +282,18 @@ create_1d_filter (int              width,
>>             p[x] = t;
>>         }
>>
>> +       /* Distribute any remaining error over all samples */
>>         if (new_total != pixman_fixed_1)
>> -           p[width / 2] += (pixman_fixed_1 - new_total);
>> +       {
>> +           pixman_fixed_t delta = new_total - pixman_fixed_1;
>> +           pixman_fixed_t t = 0;
>> +           for (x = 0; x < width; ++x)
>> +           {
>> +               pixman_fixed_t new_t = delta * (x + 1) / width;
>> +               p[x] += new_t - t;
>> +               t = new_t;
>> +           }
>> +       }
>>
>
> I think there is a sign error in this code: delta is new_total - 1, which
> is positive when new_total is bigger than 1. But this positive delta is
> then added to the samples, making the total even bigger.
>
> Also, I would write the code like this:
>
>         pixman_fixed_t error = pixman_fixed_1 - new_total;
>         for (x = 0; x < width; ++x)
>         {
>             pixman_fixed_t d = error * (x + 1) / width;
>             p[x] += d;
>             error -= d;
>         }
>
> to get rid of the temporary and to make it more obvious that there is an
> error that is being distributed.
>
> Another possibility is to do error diffusion in the /* Normalize */ loop.
>

Also, a test that generates a bunch of filters and verifies that all the
phases sum to 1 would be useful.


Søren
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