Witam Loguje sie przez ssh na zwyklego uzytkownika, ale mam dziwny problem. Wyglada to tak: [EMAIL PROTECTED] poul]$ ssh [EMAIL PROTECTED] Password: Password: Password: [EMAIL PROTECTED]'s password: Last login: Tue Feb 24 13:23:32 2004 from penetrator
Czyli 3 razy sie mnie pyta o jakies haslo, a dopiero potem jak wpisuje 4 raz to dopiero mnie wpuszcza. Wydaje mi sie ze jest to cos z tym zwiazane. [EMAIL PROTECTED]'s password: Permission denied, please try again. [EMAIL PROTECTED]'s password: Permission denied (publickey,password,keyboard-interactive). [EMAIL PROTECTED] poul]$ Moze powinno byc najpierw password ?? O co chodzi ?? Srodowisko PLD AC. [EMAIL PROTECTED] /root]# rpm -qa openssh pam pam-0.77.3-7 openssh-3.7.1p2-4.5 Prosze o pomoc, bo to troszeczke uciazliwe. Aha, loguje sie z Mandrake 9.1 (wczesniej, z PLD takich problemow nie bylo, ale wyrzucilem stary komputer, wstawilem nowy, zainstalowalem PLD AC i z kernel-smp-2.6.3-1.6 i mam takie problemy). Sprawdzilem z debiana i wyglada tak samo, najpierw 3 hasla widmo, a dopiero potem wlasciwe. Z debiana sie logowalem na te nieszczesne PLD. A w logach mam cos takiego: Feb 24 13:20:13 penetrator sshd[21172]: error: PAM: Authentication failure Feb 24 13:20:16 penetrator sshd(pam_unix)[21207]: authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=penetrator user=poul Feb 24 13:20:18 penetrator sshd[21172]: error: PAM: Authentication failure Feb 24 13:20:18 penetrator sshd[21172]: Postponed keyboard-interactive for poul from ::ffff:195.136.250.238 port 33662 ssh2 Feb 24 13:20:39 penetrator sshd(pam_unix)[21234]: authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=penetrator user=poul Feb 24 13:20:42 penetrator sshd[21172]: error: PAM: Authentication failure Feb 24 13:20:42 penetrator sshd[21172]: Failed keyboard-interactive/pam for poul from ::ffff:195.136.250.238 port 33662 ssh2 Feb 24 13:20:47 penetrator sshd[21172]: Accepted password for poul from ::ffff:195.136.250.238 port 33662 ssh2 Feb 24 13:20:47 penetrator sshd(pam_unix)[21374]: session opened for user poul by poul(uid=0) Feb 24 13:20:54 penetrator su(pam_unix)[21421]: session opened for user root by poul(uid=500) Feb 24 13:20:54 penetrator pam_xauth[21433]: call_xauth: execve failed for /usr/X11R6/bin/xauth Feb 24 13:20:54 penetrator pam_xauth[21421]: call_xauth: child returned 1 _________________________________________ http://pld-linux.org/ = faq, howto, newsy dostales tutaj odpowiedz na swoje pytanie? podziel sie z innymi i dopisz do FAQ! http://pld-linux.org/FAQ/