I'm using bc and it is ok. The problem is I cannot put a number next to the
output. I cannot command the echo with "-n parameters". After I get the value,
I need to put another value next to it which is having an error
if [ $grep2a_1 -eq "1" ];
then
echo -n "$time,"
echo "scale=3; $com2_1 / 1000" | bc (If I change this line to echo -n
"scale=3; $com2_1 / 1000" | bc, it has an error)
else
echo "test"
fi
----- Original Message ----
From: andrelst <[EMAIL PROTECTED]>
To: Philippine Linux Users' Group (PLUG) Technical Discussion List
<plug@lists.linux.org.ph>
Sent: Saturday, December 1, 2007 10:22:13 AM
Subject: Re: [plug] How to display remainder in Bash script
expr only does integers, which the man pages in Linux sadly omits.
Solaris explicitly says it in the man page that it's only for
integers.
go for bc if you want remainders:
$ echo 5 / 3 | bc -l
1.66666666666666666666
--
regards,
Andre | http://www.varon.ca
On Nov 30, 2007 8:49 PM, Nelson Serafica <[EMAIL PROTECTED]> wrote:
>
>
> I'm trying to create a script that will convert b/s to kb/s. To
convert to
> kb/s, I must divide it to 1000 b/s. However, the answer does not
contain the
> remainder. When I do "expr 5 / 3", it shows only 1 (suppose to be
1.6).
> Doesn't show the remainder .6.
>
> I search in Google and it says the "%" is remainder of a division.
But when
> I do expr 5 % 3, it shows "2". It suppose to be 6, am I right?
>
>
> Any inputs,
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