Try using awk
ls -l | awk '{print $1 $$NF;}'
Note if the file timestamp (creation or modification) is over a year old it
changes and the output may not have 9 columns then.
On Mon, Nov 7, 2016 at 7:47 AM, Rich Shepard <rshep...@appl-ecosys.com>
wrote:
> I tried using cut to list permissions and filenames from a directory
> listing, example:
>
> ls -l | cut -d"\b" -f 1,9 > temp.txt
>
> but the delimiter is more than a single character. Using -d " " for the
> delimiter does not work as there are more than a single space separating
> fields, and the white space is not uniformly a tab.
>
> The man page and results from my web searches haven't shown me how to
> correctly specify the delimiter.
>
> Here's an example listing from ~/;
>
> $ ls -l | head
>
> -rw-r--r-- 1 rshepard users 14 Nov 5 08:30 CURRENTIP
> drwxrwxr-x 2 rshepard users 4096 Nov 8 2010 Desktop/
> drwx------ 2 rshepard users 4096 Oct 18 2014 Downloads/
> drwx------ 8 rshepard users 4096 Nov 7 05:39 Dropbox/
> drwxr-xr-x 2 rshepard users 4096 Jul 6 08:31 News/
> drwxrwxr-x 44 rshepard users 4096 Nov 4 10:47 R/
> -rw-r--r-- 1 rshepard users 2569555 Oct 31 16:29 rue2009.pdf
> -rw-r--r-- 1 rshepard users 14052 Dec 4 2015 UTF-8-demo.txt
> -rw-r--r-- 1 rshepard users 1318075 Oct 25 10:16 al-rawas2011.pdf
>
> and I want to extract fields 1 and 9.
>
> TIA,
>
> Rich
>
>
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