Title: RE: [plug] [OT]Question in C programming

Hi Orly and Jeff,

 I found a definition of __P in some of the includes, and it says

 #define __P(args) args

 or

 #define __P(args) args throw()

 
 I wonder what is the effect of using it?  by the way what's throw()?
 
Thank you very much =)

Jeffrey

-----Original Message-----
From: Orlando Andico
To: '[EMAIL PROTECTED] '
Sent: 3/6/2001 3:10 PM
Subject: Re: [plug] [OT]Question in C programming

On Tue, 6 Mar 2001, Jeffrey Wong wrote:
..
>  I am trying to study some C codes, and encountered the following line
in
> one of the header declarations
>
>  void new_phase __P((int));
>
>  What does __P means?

It's a cast to something. look in /usr/include there's probably a
definition there. I would hazard, it's a 32-bit void pointer.

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