On 12/15/17 11:55, Galen Seitz wrote: > Hi, > > Can anyone suggest a quick way to get a count of the number files owned > by each uid, or alternatively, print each unique uid that exists in the > filesystem? Bonus points for doing the same thing for gid's in the same > pass.
Thanks for the other suggestion. I finally used the correct search terms and found what I wanted. I'm running this now, but it's taking a while. find / -path /tmp -prune -o -path /sys -prune -o -path /proc -prune -o -printf %u:%g\\n | awk '{usergroup[$0]++}; END {for(key in usergroup) printf "%-20s %d\n",key,usergroup[key]}' Next time I will probably add "-uid +499", as I'm not interested in system accounts. galen -- Galen Seitz gal...@seitzassoc.com _______________________________________________ PLUG mailing list PLUG@pdxlinux.org http://lists.pdxlinux.org/mailman/listinfo/plug