Look at the following bash code: #!/bin/bash func () { echo "\"loc_var\" in func = $loc_var" }
func2 () { echo "loc_var inside another function is" $loc_var local loc_var=23 func } loc_var=43 func2 echo "\"loc_var\" outside function = $loc_var" exit 0 If you run this, you'll notice that loc_var prints as 23. It should print as 43. This is a problem with bash - that is if one function calls another the value of the local variables are seen. Does the C shell handle this correctly? /* PLUG: http://plug.org, #utah on irc.freenode.net Unsubscribe: http://plug.org/mailman/options/plug Don't fear the penguin. */