I tried to restart lineno with something like Francesco's
my_lexer.lineno = 0
but it didn't worked. I've tried again and it works fine ¬¬
Anyway, I've done lex.lex().lineno = 1, because I need the first line
to be line 1, not line 0 ;)
Thanks for your help!!
On Aug 26, 4:41 pm, Francesco Bochicchio <[EMAIL PROTECTED]> wrote:
> On Aug 24, 7:27 pm, "Dave!" <[EMAIL PROTECTED]> wrote:
>
>
>
>
>
> > Hello!
> > I'm using PLY-2.3 to build a C language compiler, and I need to know
> > if there's any way to restart the lineno counter between lexical and
> > syntactic analysis.
>
> > What I mean with that is that, first of all, I analyze the source
> > code and show the tokens found by the lexer with lex.token() function.
> > With that I obtain tokens that look like this: LexToken(RBRACE, '}',
> > 22, 485). The problem comes with the syntactic analysis, where I use
> > yacc.parse() function. At this point, when it detects an error I made
> > it print the token that caused it, but the line number isn't the real
> > line number, it doesn't restart the lineno counter between lex.token()
> > and yacc.parse().
>
> > For example, in a source code with 20 lines, lex.token() says that
> > line 1 is line 1, but yacc.parse() says that line 1 is line 21...
>
> > What can I do??
>
> My only suggestion (which probably you already know) is to try and
> reset the 'lineno' attribute of your lexer.
> Something like (not tested):
>
> my_lexer = lex.lex()
> my_lexer.input(text_to_parse)
> my_lexer.lineno = 0
> my_lexer.input(text_to_parse) # I guess...
> my_parser = yacc.yacc( lexter=my_lexer )
> my_parser(parse)
>
> Ciao
> -----
> FB- Hide quoted text -
>
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