On 21 July 2011 15:44, p valdes <p.valdes...@gmail.com> wrote:
> mmmh... I see
>
> Thanks a lot for your advice Nicolas, I will follow your clue and
> investigate about how to do this
>

Something like:

SELECT st_area(st_transform(mytable.perimeter, 32630)) AS square_meters
FROM mytable
WHERE name = 'myname';

Should give you areas in square meters.

Nicolas
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