I apologize if I am being naive here, but is it fair to say that for an FFT size of 1024K (2^20), a number (MOD the exponent) is split into the 2^20 digits (base 32) for input?
The output is then 2^20 floating point numbers, each of which is rounded to the nearest integer? David _________________________________________________________________ Be one of the first to try Windows Live Mail. http://ideas.live.com/programpage.aspx?versionId=5d21c51a-b161-4314-9b0e-4911fb2b2e6d _______________________________________________ Prime mailing list [email protected] http://hogranch.com/mailman/listinfo/prime
