Maybe something like ..
STORE CAST(0 AS I) TO lnCheck
lcDtString = STRCONV(DTOS(DATE()), 12)
=ALINES(laValues, m.lcDtString, 0, CHR(0))
FOR lnPosn = 1 TO 8
STORE VAL(laValues(m.lnPosn)) TO lnVal
? lnVal
IF BITTEST(m.lnCheck, m.lnVal)
*- Have a duplicate number - do what ever
=MESSAGEBOX(laValues(m.lnPosn) + " appears more than once.")
EXIT
ELSE
STORE BITSET(m.lnCheck, m.lnVal) TO lnCheck
ENDIF
ENDFOR
-----Original Message-----
From: ProfoxTech [mailto:profoxtech-boun...@leafe.com] On Behalf Of Gene
Wirchenko
Sent: Monday, 18 July 2016 2:29 AM
To: profoxt...@leafe.com
Subject: Checking for All-Different Characters
Hello:
I write a logic/math puzzle each week. They appear in my blog
(http://genew.ca/) and two local newspapers.
Here is the latest problem:
"Consider a date in YYYY-MM-DD format. What is the next date where
all eight digits will be different?"
I solved this by hand. I decided to verify my solution with a
program. I often cook up something in GW-BASIC, but since VFP has date
functions, I decided to go with it.
It was very easy to set up the framework of the loop. What threw me
for a loop is how to check that all of the digits are different. I ended up
converting the date to string with dtos() and then testing the string with a
rather ugly-looking condition. Is there something faster?
***** Start of Code *****
* 16s-16.prg
* Date Puzzle
* Last Modification: 2016-07-17
*
* Consider a date in YYYY-MM-DD format. What is the next date where all
* eight digits will be different?
? "*** Execution begins."
? program()
close all
clear all
set talk off
set exact on
set century on
set date ansi
*
local startdate
startdate=date()
? "Start Date: "+transform(startdate)
local trydate, looping
trydate=startdate
looping=.t.
do while looping
local trydtos
trydtos=dtos(trydate)
if right(trydtos,4)="0101"
? "Working on year "+left(trydtos,4)
endif
if;
iif("0"$trydtos,1,0)+;
iif("1"$trydtos,1,0)+;
iif("2"$trydtos,1,0)+;
iif("3"$trydtos,1,0)+;
iif("4"$trydtos,1,0)+;
iif("5"$trydtos,1,0)+;
iif("6"$trydtos,1,0)+;
iif("7"$trydtos,1,0)+;
iif("8"$trydtos,1,0)+;
iif("9"$trydtos,1,0)#8
trydate=trydate+1
else && solution
looping=.f.
endif
enddo
? "Solution is "+transform(trydate)+"."
*
close all
clear all
? "*** Execution ends."
return
***** End of Code *****
Sincerely,
Gene Wirchenko
[excessive quoting removed by server]
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