Vince Teachout wrote:
> Jaime Vasquez wrote:
>> Vince Teachout writes:
>>
>>> This is a little hard to explain, but I need to get a count of distinct
>>> codes within orders. For example:
>>>
>>> Order 1:
>>> code1
>>> Code 1
>>> code 1
>>> code 2
>>> code 3
>>>
>>> Order 2:
>>> code 1
>>> Code 3
>>>
>>> I'd like to see:
>>> "Code 1", 2
>>> "Code 2", 1
>>> "Code 3, 2
>>>
>>> ie, distinct within orders, but then a count of codes for all orders.
>>> Anyway to do it in one shot? I'm pretty sure I can do it in 2 queries.
>>> Thanks.
>>
>> create cursor codes (order1 char(10), code char(10))
>>
>> insert into codes values("Order 1", "code 1")
>> insert into codes values("Order 1", "code 1")
>> insert into codes values("Order 1", "code 1")
>> insert into codes values("Order 1", "code 2")
>> insert into codes values("Order 1", "code 3")
>> insert into codes values("Order 2", "code 1")
>> insert into codes values("Order 2", "code 3")
>>
>>
>> select code, count(code) from codes group by code
>
> No, because I'm trying to get Count( distinct codes), so I'd want to see
> the results posted above. Your example just gives me a straight count:
> code 1, 4
> code 2, 1
> code 3, 2
>
>
> I've already done it using 2 selects, was just curious about doing it in
> one. Thank you, though.
>
select code, count(code) ;
from ( ;
select order, code ;
from codes ;
group by order, code ;
) mycodes ;
group by code
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