I'm still at the stage where I have to read the dictionary entry for most of the
verbs, so I'm not even in the slow lane yet. Looking at Stitch (dyadic ,.)[1] I was
reminded of the explanation of u"_1, which suggested using Link (dyadic ;)[2]
g =: }. @ (; @ (;"_1))
' ' g t
alpha bravo chuck
LF g t
alpha
bravo
chuck
if you like "pipelining" your verbs. (The outer set of parens aren't needed in
g , but that's a subtly different pipeline.)
... peter
[1] http://www.jsoftware.com/docs/help701/dictionary/d321.htm
[2] http://www.jsoftware.com/docs/help701/dictionary/d330.htm
Linda Alvord wrote:
In the slow lane, here's a version without @ or &. or even inv .
t=: 'alpha' ; 'bravo' ; 'chuck'
}.@((<' ') ;@,. ]) t
alpha bravo chuck
}: ; t,&.> ' '
alpha bravo chuck
}.(<' ')([:;,.) t
alpha bravo chuck
Linda
-----Original Message-----
From: programming-boun...@forums.jsoftware.com
[mailto:programming-boun...@forums.jsoftware.com] On Behalf Of Linda Alvord
Sent: Friday, September 07, 2012 4:07 PM
To: programm...@jsoftware.com
Subject: Re: [Jprogramming] Flattening a list containing boxed elements
Thanks, After I sent the message it rankled me that it might be a problem of
rank.
Linda
-----Original Message-----
From: programming-boun...@forums.jsoftware.com
[mailto:programming-boun...@forums.jsoftware.com] On Behalf Of Dan Bron
Sent: Friday, September 07, 2012 12:35 PM
To: programm...@jsoftware.com
Cc: <programm...@jsoftware.com>
Subject: Re: [Jprogramming] Flattening a list containing boxed elements
Rank. All definitions in the DoJ are subject to considerations of rank, though this often -forgive the pun- tacit.
NB. vi (v x) u (v y)
glue =: dyad def '< (> x) , (> y)'
NB. Rank zero here is key
; z glue"0 ' '
alpha bravo chuck
-Dan
Please excuse typos; composed on a handheld device.
On Sep 7, 2012, at 11:22 AM, "Linda Alvord" <lindaalv...@verizon.net> wrote:
Now what am I missing?
; z ,&.> ' '
alpha bravo chuck
NB. x u&.v y ↔ vi (v x) u (v y)
;<(>z),>' '
alpha
bravo
chuck
Linda
-----Original Message-----
From: programming-boun...@forums.jsoftware.com [mailto:programming-
boun...@forums.jsoftware.com] On Behalf Of Linda Alvord
Sent: Friday, September 07, 2012 11:00 AM
To: programm...@jsoftware.com
Subject: Re: [Jprogramming] Flattening a list containing boxed
elements
Chuck caused grief!
-----Original Message-----
From: programming-boun...@forums.jsoftware.com
[mailto:programming-boun...@forums.jsoftware.com] On Behalf Of Dan
Bron
Sent: Friday, September 07, 2012 9:24 AM
To: programm...@jsoftware.com
Cc: <programm...@jsoftware.com>
Subject: Re: [Jprogramming] Flattening a list containing boxed
elements
There are more issues than that. For example, try it with "chuck"
instead of "charlie".
Also, since > is a scalar verb, the "0 is superfluous. Also, the ,' '
appends spaces not to the individual words, but to the entire array,
so that they all end up trailing, instead of interspersed as desired
(the spaces which separate the words in Linda's final result are an
[undependable] side-effect of >, and the experiment suggested above
may hint at their origin).
But, like newcomer to a foreign tongue, Linda has certainly made
herself understood, and the idea is spot on, even if the words aren't exact.
Certainly we do want to:
get inside
"0 each box
,' ' append a space
, and string the whole thing together.
A native speaker might have said ; z ,&.> ' ' (and a fastidious
speaker would prepend a }: ).
-Dan
Please excuse typos; composed on a handheld device.
On Sep 7, 2012, at 8:02 AM, "R.E. Boss" <r.e.b...@planet.nl> wrote:
z=: 'alpha' ; 'bravo' ; 'charlie'
' '=,(>"0 z),' '
0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 1
' '=;:^:_1 z
0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0
R.E. Boss
-----Oorspronkelijk bericht-----
Van: programming-boun...@forums.jsoftware.com
[mailto:programming-boun...@forums.jsoftware.com] Namens Linda Alvord
Verzonden: vrijdag 7 september 2012 12:50
Aan: 'Programming forum'
Onderwerp: Re: [Jprogramming] Flattening a list containing boxed
elements
Did I miss this somewhere? An alternative without inv.
,(>"0 z),' '
alpha bravo charlie
Linda
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