NB. ({:"1 A) equals {."1 B
so not the leading column of A
Perhaps I should have added that ({:"1 A) =&~. {."1 B
or all not matching rows are deleted.
R.E. Boss
> -----Oorspronkelijk bericht-----
> Van: [email protected]
> [mailto:[email protected]] Namens Raul Miller
> Verzonden: maandag 15 oktober 2012 18:24
> Aan: [email protected]
> Onderwerp: Re: [Jprogramming] stitching matrices
>
> Given your description, I would have expected a result like this:
>
> 0 1 2 0 1 1 2 0
> 0 1 2 0 1 1 2 0
> 2 0 1 2 0 0 1 2
> 1 2 0 1 2 2 0 1
> 1 2 0 1 2 2 0 1
>
> I do not understand the result you proposed.
>
> Also, you have not specified what happens for rows where the leading
> column of A has a value which does not appear in the leading column of
> B. I can imagine several treatments for this case:
>
> 1) error
> 2) join to a row of fills
> 3) eliminate the row from the result
>
> Likewise for the reverse case, where the leading column of B has a
> value which does not appear in the leading column of A. (And, the
> asymmetric treatment of A and B, where one of the columns of B does
> not contribute to the result, makes me wonder if the treatment for
> {."1 A not in {."1 B might be different from from the treatment of
> {."1 B not in {."1 A.)
>
> So... I am confused. Any clarification or explanation you can provide
> could help.
>
> Thanks,
>
> --
> Raul
>
> On Mon, Oct 15, 2012 at 10:59 AM, R.E. Boss <[email protected]> wrote:
> > Given
> >
> > ['A B' =. 3|L:0<@i."(1)3 5,: 5 4
> > +---------+-------+
> > |0 1 2 0 1|0 1 2 0|
> > |2 0 1 2 0|1 2 0 1|
> > |1 2 0 1 2|2 0 1 2|
> > | |0 1 2 0|
> > | |1 2 0 1|
> > +---------+-------+
> >
> > I want to stitch every row from A with all rows from B where ({:"1 A)
> > equals {."1 B and one of these columns is deleted.
> > This will give me
> >
> > A foo B
> > 0 1 2 0 1 2 0 1
> > 0 1 2 0 1 2 0 1
> > 2 0 1 2 0 1 2 0
> > 2 0 1 2 0 1 2 0
> > 1 2 0 1 2 0 1 2
> >
> > Any elegant solutions?
> >
> >
> > R.E. Boss
> >
> > ----------------------------------------------------------------------
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