Marshall Lochbaum <mwlochb...@gmail.com> writes: > I'm confused about how you are handling multiple values for one of the > attributes (like Attribute 1 here). If you give more detail I can give > some hints on that. Of course, if you can do it yourself, that's even > better!
Marshall, You handled multiple values as I want in your third step (see charlie delta below). >> d2 =: 0 : 0 >> Attribute 0: alpha >> Attribute 1: bravo >> Attribute 2: charlie delta >> Location: echo >> Attribute 3: hotel >> Attribute 0: alpha >> Attribute 1: bravo >> Attribute 2: charlie delta >> Location: foxtrot >> Attribute 3: hotel >> Attribute 0: alpha >> Attribute 1: bravo >> Attribute 2: charlie delta >> Location: golf >> Attribute 3: hotel >> Attribute 0: india >> Attribute 1: juliet >> Attribute 2: kilo >> Location: lima >> Attribute 3: >> ) You ended up combining hotel and india as Attribute 3, but india is Attribute 0 for the next entry. If I call your last calculation d4, and do d5 =: > d4 Now the other missing steps, which I'll work on tomorrow, are to - copy the attributes for alpha over for locations foxtrot and golf - fold the attributes for india up with the rest - transpose the array to get a spreadsheet layout with attributes across the top and data down below. Thanks. I had taken a different tack, using cut to create a Boolean vector for each of the attributes to mark the start of the attribute and then searching for a way to pull out each of the attributes into one box each. I got stuck there. Bill -- Bill Harris Facilitated Systems http://makingsense.facilitatedsystems.com/ ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
