Thank you.

I had tried to do something similar, but I couldn't come up with a decent 
ambivalent verb to use.

Now for the big question. Even-numbered and odd-numbered dyadic trains behave 
very differently. Is there a purpose behind this difference? Or is it just a 
product of the other rules?

In my very humble opinion, even-numbered dyadic trains look out of place. They 
lose their "dyadicness" early on and expand into a monadic train:

(x (F e D c B a) y)  -:  x F (e D c B a) y

— 
Tobia


On 22 Jul 2013, at 02:43, Raul Miller wrote:

> That looks right, to me.
> 
> Note that you can test this if you replace := with -:
> 
> For example:
> 
> x=: 1
> y=: 2
> a=:B=:c=:D=:e=:F=: <@,&<
> 
> Thanks,
> 
> -- 
> Raul
> 
> 
> On Sun, Jul 21, 2013 at 7:53 PM, Tobia Conforto
> <[email protected]> wrote:
>> Hello
>> 
>> I'm trying to understand trains of verbs and I came up with this. Can 
>> anybody please either confirm it or correct me?
>> 
>> Monadic trains:
>> 
>>            (B a) y  :=                 y  B (a y)
>>          (c B a) y  :=              (c y) B (a y)
>>        (D c B a) y  :=         y  D (c y) B (a y)
>>      (e D c B a) y  :=      (e y) D (c y) B (a y)
>>    (F e D c B a) y  :=  y F (e y) D (c y) B (a y)
>> 
>> Dyadic trains:
>> 
>>          x (B a) y  :=                     x  B (  a y)
>>        x (c B a) y  :=                (x c y) B (x a y)
>>      x (D c B a) y  :=           x  D (  c y) B (  a y)
>>    x (e D c B a) y  :=      (x e y) D (x c y) B (x a y)
>>  x (F e D c B a) y  :=  x F (  e y) D (  c y) B (  a y)
>> 
>> Capped fork in even-numbered dyadic train:
>> 
>> x (F e  D c  B a) y  :=  x F (e y) D (c y) B (a y)
>> x (F e  D [: B a) y  :=  x F (e y) D       B (a y)
>> x (F [: D c  B a) y  :=  x F       D (c y) B (a y)
>> x (F [: D [: B a) y  :=  x F       D       B (a y)
>> 
>> Capped fork in odd-numbered dyadic train:
>> 
>>  x (e  D c  B a) y  :=  (x e y) D (x c y) B (x a y)
>>  x (e  D [: B a) y  :=  (x e y) D         B (x a y)
>>  x ([: D c  B a) y  :=          D (x c y) B (x a y)
>>  x ([: D [: B a) y  :=          D         B (x a y)
>> 
>> 
>> -Tobia
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