9!:3 [ 2 4
+&+&+:
┌───────┬─┬──┐
│┌─┬─┬─┐│&│+:│
││+│&│+││ │ │
│└─┴─┴─┘│ │ │
└───────┴─┴──┘
┌─ +
┌─ & ─┴─ +
── & ─┴─ +:
And looking at compose page (
http://www.jsoftware.com/help/dictionary/d630v.htm) we get
(+: 2) +&+ (+: 3)
I still don't understand the parsing rules enough to know how more
complicated expressions/trains get parsed by J.
Pardon if this is mere noise.
On Sun, Mar 2, 2014 at 10:33 AM, Pascal Jasmin <[email protected]>wrote:
> That is indeed the problem, but the code
>
> 2 +&+&+: 3
>
>
> is not 2 + 2 +&+: 3
>
> but rather
> 0 + 2 +&+: 3
> 10
> when it should be:
> + 2 +&+: 3
> 10
>
> There doesn't seem to be a good reason to insert 0 v in it. This is weird
> though:
>
> 2 ([: +: ])&(+&+:) 3
> 12
>
> I don't think it is:
>
> 2+ 2 +&+:3
>
> which seems to have nothing to do with supplied verbs. So more likely:
>
> +: (+ +: 3)
>
> and x argument is discarded completely. (it should have applied to 2 +&+:
> 3, and above result should be 20)
>
>
> ----- Original Message -----
> From: Don Guinn <[email protected]>
> To: Programming forum <[email protected]>
> Cc:
> Sent: Sunday, March 2, 2014 10:02:31 AM
> Subject: Re: [Jprogramming] bug in & ?
>
> I think the problem is that the left-most +: is not-or and only accepts
> boolean arguments.
>
> 0 +:&+&+: 0
> 1
>
>
>
> On Sun, Mar 2, 2014 at 7:53 AM, Pascal Jasmin <[email protected]
> >wrote:
>
> > +:&+&+: 3
> > 12
> > 2 +&+&+: 3
> > 10
> >
> >
> > 2 +:&+&+: 3
> > |domain error
> > | 2 +:&+&+:3
> >
> >
> > The 3rd verb (leftmost) is called dyadically (with 0 element? like /?)
> > even though it sees only a monadic expression.
> > ----------------------------------------------------------------------
> > For information about J forums see http://www.jsoftware.com/forums.htm
> >
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm
>
> ----------------------------------------------------------------------
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>
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