On Thu, Apr 24, 2014 at 12:06 AM, Pascal Jasmin <[email protected]>wrote:
> ${.^: (1 = $) }:^:(a: = {:) 3 ; i.0
> 1
>
$ ]^:1 'a'
$ ]^:(,1) 'a'
1
In other words, the result of 1 = $ is a list and that structure becomes a
part of your result.
Thanks,
--
Raul
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