That is very close to what I came up with, for the case where we want only
a single value from our result:
d6=:1 + ? bind 6
repd6=: [:+/(,d6)^:(6={:)@d6
Here's a variation on Roger Hui's approach, for the case where we want N
values from our result:
d6s=: 1 + [: ? #&6
bulk=:{.#&0(],~(+/;.1~1:}:@,0~:6&|)@(],d6s@[))^:(0=6&|@{:@{.)^:_~]
Example use:
bulk 20
5 5 5 4 3 3 2 3 3 9 1 4 16 3 3 1 3 17 3 4
This would probably be much clearer if implemented explicitly rather than
tacitly, and probably would be more efficient also. So:
bulkd6s=:3 :0
r=. i. 0
while. y >: #r do.
r=. r, d6s y
mask=. }: 1, 0~:6|r
r=. mask +/;.1 r
end.
y{.r
)
But statistically speaking, this is still not as efficient as it could be.
I think we'd do better with:
bulkd6=:3 :0
r=. i. 0
while. y >: #r do.
r=. r, d6s 2*y
mask=. }: 1, 0~:6|r
r=. mask +/;.1 r
end.
y{.r
)
Do you see why this tends to be more efficient?
Thanks,
--
Raul
On Thu, Sep 25, 2014 at 11:50 AM, 'Pascal Jasmin' via Programming <
[email protected]> wrote:
> this works
>
> (, >:@?@6:)^:((0=#) +. 6={:)^:_ i.0
>
> ([: +/ (, >:@?@6:)^:((0=#) +. 6={:)^:_) i.0
> 11
>
>
>
> ----- Original Message -----
> From: Johann Hibschman <[email protected]>
> To: Programming forum <[email protected]>
> Cc:
> Sent: Thursday, September 25, 2014 9:06 AM
> Subject: [Jprogramming] Repeated rolling dice
>
> Hi all,
>
> For fun, I've been running some statistics for a game with an unusual
> rule for rolling dice: if a 6 is rolled, roll again and add the
> result, repeating on any subsequent 6s. I wanted to implement this in
> J, collecting all the individual rolls (rather than just the sum.)
>
> It seems like there should be a more clever and elegant way to do
> this, but this is what I have:
>
> NB. Simple roll.
> roll0 =: >:@?
>
> NB. This seems to work, but it's not very clever.
> roll =: 3 : 0
> r =. >:?y
> if. r=y do. r=. r,(roll y) end.
> r
> )
>
> NB. Attempt at iterating via power. Fails because repeats
> NB. signal termination.
> roll0^:(6&=)^:(<_) 6
>
> NB. Attempt at iterating via agenda. Not even close yet.
> NB. ]`(]+$:) @. (=&6) NB. where to stick in the roll?
>
> This gives what I expect:
>
> roll"0 ] 10#6
> 6 1 0
> 3 0 0
> 3 0 0
> 2 0 0
> 5 0 0
> 2 0 0
> 6 6 2
> 2 0 0
> 1 0 0
> 6 3 0
>
> But is there a better way to do this? Also, are there any known issues
> with the RNG? I've not gathered enough statistics to prove it, but the
> results look clumpier (more identical values in a row) than I expect.
> Now, I know that's a common cognitive bias, so it may just be me, but
> is there a discussion of the quality of the RNG somewhere?
>
> Thanks,
> Johann
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>
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