I have been trying to understand the hex conversion 3!:3
(see : http://www.jsoftware.com/docs/help701/dictionary/dx003.htm )
but cannot understand what the result is.
If I define
tohex =: 3!:3
and I want to choose to represent my integer in standard byte order hex, I can
do:
0 tohex 15
which gives,
e0000000
00000004
00000001
00000000
0000000f
It seems what I want is in the last row (0000000f = 15). But what does all the
rest mean?
Thanks.
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