I do not think updating y is what I need in this case.In pseudocode, an example 
is
x = 3; //just some start value for xy; //some arrayfor (i = 0; i < max; i+= 4){ 
x = myVerb(x, y[i], y[i+1], y[i+2], y[i+3]); //my verb is equivalent(~ish) to  
verb u.}
return x;
So I thought using u\ would be a good way to do the forloop. The problem, of 
course, is that the previous iteration's result of myVerb is the next 
iterations myVerb parameter.
I'm not wedded to the idea of using u\, and I am beginning to wonder if it is 
completely inappropriate for doing this.
> Date: Wed, 3 Dec 2014 01:27:39 +0000
> From: [email protected]
> To: [email protected]
> Subject: Re: [Jprogramming] Modifying x inside Infix
> 
> The argument to 4 u\ y will be entirely y, and u is monadic.
> 
> you can do something like this though:
> 
> 2 (3&+)\ i.5 
> 3 4 
> 4 5 
> 5 6 
> 6 7 
> 
> 
> If you can change your spec to "updating y" on every iteration, and you want 
> to apply to: 
> 
> x1 u (x2 u y)
> then you can make a table where x1, x2 and y are the 3 rows, and then call 
> with u/.  You can search for boxscan in archives for method where x and y are 
> not the same shape.  This is generally preferable to trying to keep a side 
> effect between calls (so you don't need to worry about initializing it)
> 
> 
> ________________________________
> From: Jon Hough <[email protected]>
> To: "[email protected]" <[email protected]> 
> Sent: Tuesday, December 2, 2014 7:58 PM
> Subject: [Jprogramming] Modifying x inside Infix
> 
> 
> If y is a list and I have a dyadic verb u, which I want to apply to every 4 
> items of y I can do
> 
> x ( 4 u \) y
> 
> 
> and this will apply x u to every 4 items.
> 
> 
> But I want to continually update x every iteration. So after doing x u y to 
> the first 4 items, x becomes the result,
> 
> 
> i.e. x =: x u y
> 
> 
> How do I do this for all the list? 
> 
> 
> I tried things like        
> result =:  leftArg ( 4 (leftArg =:) u \ )rightArg
> 
> 
> but I can't get the correct syntax (assuming there is a way to do this).
> (I hope my explanation made sense.)
> Thanks.
> 
> 
> 
> 
> 
> 
> 
>                           
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