That is a dot product, a scalar zero on the left and a matrix on the right.
If you follow the rules of a dot product the scalar zero is treated as (1
2$0) giving the result.

On Thu, May 5, 2016 at 3:54 PM, Geoff Canyon <[email protected]> wrote:

> So there are a few learning opportunities here -- euphemism for things I
> don't understand ;-)
>
> I get how adding 0 = transforms the modulo results into a 1 for "divisible"
> and 0 for "not divisible":
>
>       3 5 (0 = (|/ i.)) 20
>
> 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0
>
> 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0
>
>
> But I'm not seeing how this combines those results with an OR:
>
>
> 3 5 (0 +./ .= (|/ i.)) 20
>
> 1 0 0 1 0 1 1 0 0 1 1 0 1 0 0 1 0 0 1 0
>
>
> Maybe I'm just not seeing how the forks/hooks resolve themselves? I seem to
> recall there was a command to get J to box a command to show how that flow
> works, but I don't remember it. Or maybe that's not it at all and I'm just
> confused.
>
>
> thx
>
>
> gc
>
> On Wed, May 4, 2016 at 11:35 PM, Raul Miller <[email protected]>
> wrote:
>
> > On Wed, May 4, 2016 at 10:35 PM, Geoff Canyon <[email protected]> wrote:
> > > So I tried to write code to solve the general case of Project Euler
> > problem
> > > 1. The problem given is to find the sum of all the positive integers
> less
> > > than 1000 that are divisible by 3 or 5. Obviously the specific case is
> > > highly optimizable. But I wanted to solve the general, with any number
> of
> > > divisors and any upper limit.
> >
> > ...
> > > Here's the code. As always, I suck at J, so improvements/suggestions
> are
> > > welcome.
> > >
> > > pe1 =: +/@(([:i.]) * 1&-@(0&i.)@*/"1@|:@(|"0 1 i.))
> >
> > Maybe:
> >   pe1=: [:+/@I. 0 +./ .= (|/ i.)
> >
> > ?
> >
> > Assuming email anti-spam bots do not eat my line for including an @
> > character. Maybe, instead:
> >
> >   pe1=: [:+/ [:I. 0 +./ .= (|/ i.)
> >
> > ...
> >
> > --
> > Raul
> > ----------------------------------------------------------------------
> > For information about J forums see http://www.jsoftware.com/forums.htm
> >
> ----------------------------------------------------------------------
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