When you look at the two trees, it seems that c01 should take longer as there
must be some extra code to produce a 1:
c0=:,@((1 0 1 */ ])^:(]`(1"_)))
c01=:,@((1 0 1 */ ])^:(]`1:))
c0
┌─ ,
│ ┌─ 1 0 1
── @ ─┤ ┌─┼─ / ───── *
│ │ └─ ]
└─ ^: ─┤
│ ┌─ ]
└─┤ ┌─ 1
└─ " ───┴─ _
c01
┌─ ,
│ ┌─ 1 0 1
── @ ─┤ ┌─┼─ / ───── *
│ │ └─ ]
└─ ^: ─┤
│ ┌─ ]
└─┴─ 1:
Linda
-----Original Message-----
From: Programming [mailto:[email protected]] On Behalf
Of Henry Rich
Sent: Friday, December 1, 2017 10:23 PM
To: [email protected]
Subject: Re: [Jprogramming] APL Exercises
I see what's happening. 1"_ produces a Boolean, while 1: produces an integer.
In this case the Boolean is better. I'm not sure whether it always would be;
what do you think?
Henry Rich
On 12/1/2017 9:12 AM, Raul Miller wrote:
> Huh...
>
> I can reproduce that 10x speed difference:
>
> timespacex 'c0 17'
> 0.078233 2.01328e8
> timespacex 'c01 17'
> 0.761976 1.61061e9
> c0
> ,@((1 0 1 */ ])^:(]`(1"_)))
> c01
> ,@((1 0 1 */ ])^:(]`1:))
>
> This seems bizarre.
>
> Thanks,
>
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