Moreover, apparently there is at least another solution, ((-2^2^X) + (2^X) +8 ) [ X=. 2.9992934709539156j_13.597080425481581 5.19549681e_16j_2.92973749e_15
On Sun, Jan 28, 2018 at 7:28 PM, Jose Mario Quintana < [email protected]> wrote: > Are you sure? > > u New > - (u %. u D.1) > > ,. (8 + (2 ^ ]) - 2 ^ 2 ^ ])New (^:(<22)) 1 > 1 > 3.44167448 > 3.25190632 > 3.03819348 > 2.7974808 > 2.53114635 > 2.25407823 > 2.00897742 > 1.86069674 > 1.82070294 > 1.81842281 > 1.81841595 > 1.81841595 > 1.81841595 > 1.81841595 > 1.81841595 > 1.81841595 > 1.81841595 > 1.81841595 > 1.81841595 > 1.81841595 > 1.81841595 > > (8 + (2 ^ ]) - 2 ^ 2 ^ ]) 1.81841595 > _8.21739086e_8 > > (8 + (2 ^ ]) - 2 ^ 2 ^ ]) 1.75379 > 1.01615682 > > PS. Notice that New is a tacit version (not shown) of Louis' VN adverb. > > > > > On Sun, Jan 28, 2018 at 5:52 PM, Skip Cave <[email protected]> > wrote: > >> Raul, >> >> You had it right in the first place. >> >> 0 = 8 + (2^x) - 2^2^x NB. Is correct, and the answer is real >> >> The answer is close to 1.75379 >> >> I wanted to know how to construct the Newton Raphson method using the >> iteration verb N described in the link: http://code.jsoftware. >> com/wiki/NYCJUG/2010-11-09 >> under "A Sampling of Solvers - Newton's Method" >> >> N=: 1 : '- u % u d. 1' >> >> Skip >> >> >> >> >> >> Skip Cave >> Cave Consulting LLC >> >> On Sun, Jan 28, 2018 at 4:38 PM, Raul Miller <[email protected]> >> wrote: >> >> > Eh... I *think* you meant what would be expressed in J as: >> > >> > 0 = 8 + (2^x) - 2^2^x >> > >> > I'd probably try maybe a few hundred rounds of newton's method first, >> > and see where that leads. >> > >> > But there's an ambiguity where the original expression (depending on >> > the frame of reference of the poster) could have been intended to be: >> > >> > 0 = 8 + (2^x) + _2^2^x >> > >> > [if that is solvable, x might have to be complex] >> > >> > Thanks, >> > >> > -- >> > Raul >> > >> > On Sun, Jan 28, 2018 at 5:25 PM, Skip Cave <[email protected]> >> > wrote: >> > > What is the best iterative way to solve this equation: >> > > >> > > (-2^2^x) + (2^x) +8 =0 >> > > >> > > >> > > Skip Cave >> > > Cave Consulting LLC >> > > ------------------------------------------------------------ >> ---------- >> > > For information about J forums see http://www.jsoftware.com/forum >> s.htm >> > ---------------------------------------------------------------------- >> > For information about J forums see http://www.jsoftware.com/forums.htm >> ---------------------------------------------------------------------- >> For information about J forums see http://www.jsoftware.com/forums.htm >> > > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
