In
n=:6 6$'O'
'='((<0; 0 1 2 3),(<1; 2 3),< 2 4 ; 5)}n
|domain error
that domain error smells like an implementation error.
That said, I might be overlooking some relevant part of the dictionary.
Thanks,
--
Raul
On Sat, Nov 23, 2019 at 2:19 PM Jimmy Gauvin <jimmy.gau...@gmail.com> wrote:
>
> Hi,
>
> is there any way of making this kind of assignment ?
>
> '='((<0; 0 1 2 3),(<1; 2 3),< 2 4 ; 5)}n
> |domain error
> | '=' ((<0;0 1 2 3),(<1;2 3),<2 4;5)}n
>
> But this works :
> '='((<1; 2 3),< 2 4 ; 5)}n
> OOOOOOOO
> OO==OOOO
> OOOOO=OO
> OOOOOOOO
> OOOOO=OO
>
> and so does :
>
> ((<0; 0 1 2 3),(<1; 2 3),< 2 4 ; 5){n
>
> OOOO
>
> OO
>
> OO
>
>
>
> Thanks
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