Thanks, Raul. You are always so prompt with your help! I am yet to decipher
your solution, but your suggestion regarding 2 column table is bang on
point.

My own approach was something like this: find nub of the 2nd column, then
for each element in the nub collect all occurences of it, and sum over the
coeffns.

On Mon, 25 Nov 2019, 21:56 Raul Miller, <[email protected]> wrote:

> Yes, definitely.
>
> For example, consider:
>
> <"1 ({:"1 (+&.>/@:({."1), (<0 1){])/. ])>v1
>
> Or,
>
>    f=: 13 :'<"1 ({:"1 (+&.>/@:({."1), (<0 1){])/. ])>y'
>    f v1
>
> That said, this example may fall apart for your general case? (I don't
> know what that is...)
>
> Specifically, I don't know why the top level structure of v1 and v2
> would be a list of boxed entities if they are always pairs. It seems
> to me that a table of two columns would be a more natural expression
> of that, if that's the case.
>
> Thanks,
>
> --
> Raul
>
>
> On Mon, Nov 25, 2019 at 11:12 AM Arnab Chakraborty <[email protected]>
> wrote:
> >
> > Dear all,
> >
> >    I am trying to implement a geometric algebra system in J. I have done
> > much of the stuff, but is getting stuck at one point. Hence this email.
> >
> > Basically, I have a list of boxes like
> >
> > v1=: (<2.3; 2 3 4), (<3.9; 1 2), <3.1; 2 3 4
> >
> > This represents a (multi)vector whose math representation is
> >
> > 2.3 * e_{234}  + 3.9 * e_{12} + 3.1 * e_{234}.
> >
> > Here the e_{...}'s are some basis vectors. As you can see, e_{234} occurs
> > twice in the list, and so this vector may be reduced to
> >
> > 5.4 * e_{234} + 3.9 * e_{12}.
> >
> > In J this should be
> >
> > v2=:(<5.4; 2 3 4), <3.9; 1 2
> >
> > I want to write a monad f such that f v1 is v2.
> >
> > Any idea?
> >
> > Thanks and regards.
> >
> > Arnab.
> > ----------------------------------------------------------------------
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> ----------------------------------------------------------------------
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