On Tue, 19 Oct 2021, Elijah Stone wrote:
The solution with a floor of k has a determinant of (k^4) + 4*k. Are
there any values for k in range such that that value is a perfect
square?
1 e. (= <.) %: (^&4 + 4&*) >:i.150
0
It appears not :/
Ah, no, I made a foolish mistake. The determinant is actually:
(k^4) + 4002 * 4 * k
If we try again:
I. (= <.) %: (^&4 + 4002 * 4&*) i.200
0 6 23 121
0, 6, and 23 are too small; but 121 may work.
] x=. (2*121) %~ (121*121) + x: %: (121^4) + 4*121*4002
1334r11
x * (<.x) * (x - <.x)
4002
A rational solution!
-E
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