NuVoc covers this issue -- see https://code.jsoftware.com/wiki/Vocabulary/ampdot

That said, my fingers know how to find things in the original
dictionary. It's more concise than NuVoc, and I find that easier to
navigate.

Thanks,

-- 
Raul

On Sat, Oct 23, 2021 at 3:36 PM More Rice <[email protected]> wrote:
>
> Thank you, Raul!
>
> Documentation keeps pointing me to NuVoc and I completely forgot about the
> extra details in the Dictionary.  Great info. Thanks.
>
> I just found this as well -
> https://code.jsoftware.com/wiki/Essays/Tacit_Expressions
>
> I'm good now.
>
> thank you.
>
> On Sat, Oct 23, 2021 at 3:30 PM Raul Miller <[email protected]> wrote:
>
> > https://www.jsoftware.com/help/dictionary/d631.htm
> >
> >    x u&.v y ↔ vi (v x) u (v y)
> >
> > Here:
> >    u is +
> >    v is *:
> >    vi is %: (or *:inv)
> >   x is 3
> >   y is 4
> >
> > So these are equivalent
> >    3 +&.*: 4
> >    %: (*:3) + (*: 4)
> >    *:inv (*:3) + (*: 4)
> >
> > I hope this makes sense.
> >
> > --
> > Raul
> >
> > On Sat, Oct 23, 2021 at 3:03 PM More Rice <[email protected]> wrote:
> > >
> > > Hello,
> > >
> > > (Sorry for the previous empty email - web page problem)
> > >
> > > please excuse another newbie question ...
> > >
> > > Ref: https://code.jsoftware.com/wiki/Vocabulary/starco
> > >
> > >    pythag =:  +&.*:
> > >    3 pythag 4
> > > 5
> > >
> > > + operated dyadically and acted on both x and y - ok.
> > >
> > > but how does *: know to act on x as well?  Isn't pythag using the monadic
> > > definition of *: to square y only?
> > >
> > > so magical ...
> > >
> > > thank you for the pointer and have a great weekend.
> > >
> > >
> > > Maurice
> > > ----------------------------------------------------------------------
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> > ----------------------------------------------------------------------
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> >
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