I do not think you get the same results using x:

I think your ".@,&'x'@> data was fine.

You could use 10#.x:".@>@> data if you don't mind the speed penalty
and excessive use of memory, but x:".@> data does not give the same
answer, and as far as I know, x: does not accept string arguments.

Am I missing something?

Thanks,

-- 
Raul

On Sat, Apr 23, 2022 at 6:46 PM Thomas Bulka
<thomas.bu...@constraintegic.net> wrote:
>
> Sorry for the noise,
>
> question can be revoked, since I found x: ...
>
> Regards,
>
> Thomas
>
> Am Sa., 23. Apr. 2022 um 23:54 Uhr schrieb Thomas Bulka
> <thomas.bu...@constraintegic.net>:
> >
> > Hello everyone,
> >
> > say, I have a boxed list of strings which represent large integers
> > (originally I imported the data from a text file):
> >
> > data =: 
> > '34823742834835345345345346546454237';'34593823489289342893498945349539'
> >
> > I want to convert the character data into integers to use them for
> > computations, but ". gives me non-extended integers, so:
> >
> > ".@> data NB. 3.48237e34 3.45938e31
> >
> > I know, of course, that I can construct an extended integer by means
> > of adding a trailing x to an integer literal. I wonder, however, how
> > this can be done automatically. I managed to get the result I want by
> > adding the trailing 'x' to the character arrays before using ". on
> > them:
> >
> > ".@,&'x'@> data NB. Works as desired
> >
> > However, intuitively this seems to be a quite strange solution and I
> > hope there is a verb which can be used to explicitly convert the
> > character strings into extended integers. Unfortunately, I've not been
> > able to find it.
> >
> > Any suggestions on this?
> >
> > Regards,
> >
> > Thomas
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