Dear All, to start in J, i use labs.
in this page, ── (23 of 35) Numbers (ctd) ───────────────────────────────── Note the "e" notation used in 2.41785e24, meaning: 2.41785 * 10^24 J has other number notations that use letters: ) 3b102 NB. base (102 in base 3) 11 my eyes are horrified by the result 11 in base 3 is (1*3^1)+(1*3^0) 4 i verifid list of power 3^i.5 1 3 9 27 81 i tried by hand to convert 102 in base 3 (1*3^4)+(2*3^2)+(3*3^0) 102 result is 1 0 2 0 and not 11 lik your sample not only 99b102 102 in base 99 result by hand is (1*99^1)+(3*99^0) but J give a strange result 99b102 9803 and the golden medal for the big foot of calculus 4b5 5 (1*4^1)+(1*4^0) 5 the number 5 in base 4 is 11 ! not only ! 5 is over the base 4 possible i do a mistake, i dont masterize J language. i try to use a best notation +/ 0 0 1 1 * 4^|. i.4 5 0 0 1 1 in base 2 result 3 in base 10 last try : 2b3 3 Best Regards, Yves ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
