some options,
if you want your adverb to always produce a verb:
1 (>:@)
>:@1
1 (>:@) 4
2 NB. increment on constant of 1 (u/m parameter)
+: (>:@) 4
9 NB. increment after applying u (double) to y
if you want "polymorphism" in your adverb to return noun result or verb
depending on u or m,
isNoun =: (0 = 4!:0 ::0:)@:<
1 {{if. isNoun 'u' do. >: m else. >:@u end.}}
2
+ {{if. isNoun 'u' do. >: m else. >:@u end.}}
>:@+
2 + {{if. isNoun 'u' do. >: m else. >:@u end.}}3
6
On Monday, July 18, 2022 at 04:03:40 a.m. EDT, Jacques Bailhache
<[email protected]> wrote:
I define an adverb which gives the successor of its argument :
advsuc =: 1 : '>: u'
1 advsuc
2
Then I define an adverb which applies its argument to 1 :
applyto1 =: 1 : '1 u'
Then I apply it to the adverbial successor :
advsuc applyto1
advsuc applyto1
Why isn't it evaluated to 2 ?
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