The initial value (x) and all subsequent results of v go into the right
argument of v.
All I'm saying is that the picture is right.
Henry Rich
On 12/6/2022 5:32 PM, Brian Schott wrote:
So, is the picture signalling that v's left argument is y, and v's right
argument is x?
If so, that's what makes no sense, to me.
Or are you saying I've got v and u backwards, like I claimed Raul does?
On Tue, Dec 6, 2022 at 5:26 PM Henry Rich <henryhr...@gmail.com> wrote:
The picture is up to date.
Henry Rich
On 12/6/2022 5:24 PM, Brian Schott wrote:
Don't you mean v instead of u.
And even so, that may be the backward stuff that was discussed for a
while
in the early Fold stages?
On Tue, Dec 6, 2022 at 5:21 PM Raul Miller <rauldmil...@gmail.com>
wrote:
You should probably spend a few minutes studying the diagram at
https://code.jsoftware.com/wiki/Vocabulary/fcap#How_should_I_define_u_and_v.3F
The short form, however, might be summarized as:
lfold=: {{ ]F..(u~) }}
rfold=: {{ ]F.:(u~) }}
I hope this makes sense,
--
Raul
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