there is
G1 =: 1 {:: ]
G0 =: 0 {:: ]
(G0 ; ".@G1) 'abc';'13.2'
On Tuesday, February 21, 2023 at 11:18:21 p.m. EST, Elijah Stone
<[email protected]> wrote:
Your routine most likely doesn't do what you want it to:
'abc ' -: 0{:: (<@:])`(<@:".)"1 >'abc';'13.2'
1
The 'abc' got padded when you opened.
You could go for ]`(".&.>)"1. Or {{y 1}~ ".&.> 1{y}}. I don't expect you're
likely to find anything much nicer.
(Had j structural under, you might say ".&.(1&{::), but it does not.)
On Tue, 21 Feb 2023, Gilles Kirouac wrote:
> I have two character strings :
>
> datatype each 'abc';'13.2'
> ┌───────┬───────┐
> │literal│literal│
> └───────┴───────┘
>
> I want to convert the second one into numerical data
>
> datatype each (<@:])`(<@:".)"1 >'abc';'13.2'
> ┌───────┬────────┐
> │literal│floating│
> └───────┴────────┘
>
> Can you simplify the above expression?
>
>
> ~ Gilles
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