Hi!
(Apologies if this is a double-post, I believe I sent it before I was
officially on the mailing list, and I don't see it in the archives).
Given:
|:xs
1 23
2 4
3 5
4 10
5 397
6 3
7 190
8 44
9 4
10 5
11 13
12 1011
13 10
14 1119
15 72
16 1
17 1
19 6
21 3
22 2
23 1
26 2
28 2
29 2
30 1
31 2
I'd like $xs to be 2 31 but you can see that 18, 20, 24, 25, and 27
are "missing".
I'd like to "fill the holes" so the first row of xs is all the
integers 1 through 31 sequentially, and to put corresponding zeros in
the second row where I've filled the holes in the first.
My thoughts have centered around using (1+i.31),.31#0 to have a 2 by
31 array with all zeros in the second row, and then shifting my
original to find the non-sequential parts with something like:
(1|.{.xs) - {.xs
But then I'm struggling to reason about a non-loopy way to put it all
together. Any help is greatly appreciated.
Kind regards,
Daniel
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