With p defined as
p=.3 4 5$?.60$50 NB. ?.
33 (($@])#:[(I.@:=),@]) p
0 2 0
2 1 1
2 3 1
~ Gilles
Le 2023-12-26 à 21:06, 'Skip Cave' via Programming a écrit :
What would a general "find the index of the value x in the array y" verb
named fixv look like?
It would work like this:
] p=.3 4 5$?60$50
10 49 11 0 4
39 33 34 32 38
49 24 43 36 41
1 21 11 14 27
7 28 38 9 26
24 42 39 12 3
8 28 33 1 4
46 40 7 49 0
10 8 49 37 39
5 45 46 39 6
7 38 32 2 7
5 10 48 16 37
45 fixv p
2 1 1
If there were more than one match, what should the output be?
Skip Cave
Cave Consulting LLC
On Tue, Dec 26, 2023 at 7:48 PM LdBeth <andp...@foxmail.com> wrote:
This is related to the question I asked several days ago,
http://jsoftware.com/pipermail/programming/2023-December/062994.html
My suggestion would be
8 (($@])#:[i.~,@]) A
1 3
Although you might want to an alternative behavior when there are
multiple matches.
LdBeth :)
In <CAMw+KcroqQ4g=
o4rkystuqvjqqqtfxpqjy38zwarncd_ttl...@mail.gmail.com>
David Pinchbeck <dpinc...@gmail.com> wrote:
Having trouble finding this in the wiki: I know that we can select from
a
table using a boxed pair
A
0 1 2 3 4
5 6 7 8 9
10 11 12 13 14
15 16 17 18 19
20 21 22 23 24
(<1 3){A
8
How do I write a verb f to do the reverse, so that
8 f A
yields the result 1 3 ?
Thanks,
David
--
David Pinchbeck
Associate Professor of Mathematics
St. Joseph's College
Standish, ME
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