Thanks to Henry and Raul for their solutions.  I am still slightly
hazy as to why one can get away with &. rather than &.: .

Henry Rich wrote:
> I don't know the exact definition of n-norm

I should have explained.

The Lp norm of a vector v is p%:(| v)^p, an obvious case for some form
of under.  The L2 norm just measures the Euclidean distance of a point
from the origin.  You can also define the Linfinity norm of v to be
the limit as p goes to infinity of Lp(v), and this has the simple form
>./ | v .  All of these norms are equivalent.

The Linfinity is used a lot in linear algebra, since you also want
matrix norms. If n is a vector norm and A is a matrix, then you can
get a matrix norm by defining n(A) to be the maximum of n(Av), where
n(v)=1. For the infinity norm, this is just >./ +/"1 A.  The
corresponding L2 norm is much more difficult to calculate.

Best wishes,

John




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