Yes, rank 1, or do the expression on each partition p .
----- Original Message ----- From: Andrew Nikitin <[EMAIL PROTECTED]> Date: Monday, January 28, 2008 5:17 Subject: [Jprogramming] Re: Perfect powers To: [email protected] > > From: Roger Hui > > > > For larger n, you may get a faster solution by > > generating all partitions p of m for which 2 The actual > perfect power would be */p^p:i.#p > > Did you mean "1 ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
