Patrick van Beek wrote: > Hi, this is my first post to the list. I would appreciate some help > understanding how J evaluates the following: > > 100 (32&+) 100
32&+ is not a monad: x m&v y ↔ m&v^:x y So 100 (32&+) 100 is ((32&+)^:100) 100, which is 3300. Best wishes, John ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
