f=: 4 : 'c-~y*0=c=. 2-~/\0,x<.+/\y' a=: 2*5+i.5 35.5 f a _10 _12 _13.5 16 18 36 f a _10 _12 _14 16 18
It is possible that the application would be better served with the separate results 10 12 13.5 0 0 (used) and 0 0 0.5 16 18 (remainder) for 35.5 f a . ----- Original Message ----- From: Roger Hui <[email protected]> Date: Wednesday, January 27, 2010 8:59 Subject: Re: [Jprogramming] Running Subtraction To: Programming forum <[email protected]> > a*_1^0>:b-+/\a gets close, with a fix-up required > for the element on the boundary. > > The result is the negation of the usage in each bin, > but unused bins retain their original values. > > > > ----- Original Message ----- > From: Raul Miller <[email protected]> > Date: Wednesday, January 27, 2010 8:45 > Subject: Re: [Jprogramming] Running Subtraction > To: Programming forum <[email protected]> > > > On Wed, Jan 27, 2010 at 10:54 AM, Alex Rufon > <alex_ru...@ist- > > systems.com> wrote: > > > [a=. 2 * 5 + i. 5 > > > 10 12 14 16 18 > > > [b=. 35.5 > > > 35.5 > > ... > > > I want to subtract a from b progressively until b is 0 so > from > > the data above I'll get the following results: > > > _10 _12 _13.5 16 18 > > > > This description does not make sense to me. > > > > Here are my guesses for where these numbers came from: > > > > _10 -: -0{a > > _12 -: -1{a > > _13.5 -: b - +/0 1{a > > 16 -: 3{a > > 18 -: 4{a > > > > But I can not figure out how my guesses relate to > > your description. > > > > If I understood your description properly, you might > > be interested in something like: > > b-+/\.&.|. a > > 25.5 13.5 _0.5 _16.5 _34.5 > > or > > 0 >. b-+/\.&.|. a > > 25.5 13.5 0 0 0 > > > > But I am not at all confident that this is what you > > are looking for. ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
