If I slightly change your BUCKETS, PRICES and TESTS in

   BUCKETS1 =: __ , ge , {: lt

   PRICES1  =:  __ , _ ,~ out   

   TESTS1=: BUCKETS1 , _

and use a verb which is equivalent to Schott's Idotr and Millers F, I get

   TESTS1 ,: PRICES1 {~  BUCKETS1 (#...@[ <:@- |....@[ I. ]) TESTS1
__   0 0.06 0.11 0.16 0.21 0.26 0.31 0.36 0.41 0.46 0.51 0.56 0.61 0.66 0.71
0.76 0.81 0.86 0.91 0.96 1.01 _
__ 0.1 0.18 0.26 0.32 0.38 0.44  0.5 0.54 0.58 0.62 0.66  0.7 0.74 0.78 0.82
0.86  0.9 0.94 0.98    1    _ _

Is this what you want?


R.E. Boss


> -----Oorspronkelijk bericht-----
> Van: [email protected] [mailto:programming-
> [email protected]] Namens Dan Bron
> Verzonden: dinsdag 16 maart 2010 15:54
> Aan: 'Programming forum'
> Onderwerp: [Jprogramming] How to use dyad I.
> 
> When using dyad I, how does one control how to handle the various edge
> conditions gracefully (specifically out-of-bounds values and
> values exactly between intervals)?
> 
>       (1) y is greater or lesser than the head or tail of x
>       (2) y is exactly equal to a value of x, and I want to
>           decide if that means it should fall to the left
>           of the value or to the right.
> 
> All of this with an eye to performance, of course (I don't want to do the
> equality outer product x=/y to handle edge conditions, for
> example).
> 
> For example, how would you solve
> http://rosettacode.org/wiki/Price_Fraction cleanly? My first quick hack
> is:
> 
>       'ge lt out'=:ALL=:|: 0 ". ];._2 noun define
>               0.00 0.06  0.1
>               0.06 0.11 0.18
>               0.11 0.16 0.26
>               0.16 0.21 0.32
>               0.21 0.26 0.38
>               0.26 0.31 0.44
>               0.31 0.36  0.5
>               0.36 0.41 0.54
>               0.41 0.46 0.58
>               0.46 0.51 0.62
>               0.51 0.56 0.66
>               0.56 0.61  0.7
>               0.61 0.66 0.74
>               0.66 0.71 0.78
>               0.71 0.76 0.82
>               0.76 0.81 0.86
>               0.81 0.86  0.9
>               0.86 0.91 0.94
>               0.91 0.96 0.98
>               0.96 1.01    1
>       )
> 
>               NB.  Price buckets; the infinities are sentinels allowing me
>               NB.  to handle any unknown price.
>               BUCKETS =: __ , _ ,~ ge , {: lt
> 
>               NB.  Test exactly at buckets, and well within buckets
>               TESTS   =:  _9999 9999 (1 _2) } }: , (,. _ ,~ 2 (+/%#)\])
> BUCKETS
> 
>               NB.  Low unknown prices = __ , high unknown = _ .
>               PRICES  =:  __ __ , _ ,~ out
> 
>               smoutput TESTS ,: PRICES {~ (_1e_16 + BUCKETS) I. TESTS
> 
> (the handling of out-of-bounds values isn't required by the RC task, but
> I'm just using the RC task to illustrate common issues I
> have with I.)
> 
> Reasons I don't like this hack (bearing in mind I didn't think much, just
> wrote code until I got a solution that mostly worked):
> 
>       (a) It's still not right (for the input 1.01 the output
>           is 1, where it should be _),
>       (b) The addition of _1e_16 feels hacky and will break if
>           I. ever gets tolerant (or under various other conditions)
>       (c) I had to prepend 2 copies of __ to prices, instead of
>           1, to get this to work.
> 
> Also, I note that the Python solution leverages a function called
> bisect.bisect_right -- implying there's a bisect.bisect_left.  Is
> I. inherently biased in one direction or the other, or is this managed by
> using different grades or applying reversals?
> 
> -Dan
> 
> 
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