Upon further thought, it doesn't quite act the same way. If you use it
dyadically it will, but returns 0 if used monadically instead of the domain
error the original solution would provide.
Cheers, bob
On 2010-12-14, at 4:52 PM, bob therriault wrote:
> Somewhat surprisingly (to me)
>
> av2=: 1 : 'm*-~'
>
> also works the same way.
>
> Cheers, bob
>
> On 2010-12-14, at 4:48 PM, Tikkanz wrote:
>
>> Or just
>> adv2 =: 1 : (':';'m*y-x')
>>
>> See http://www.jsoftware.com/help/dictionary/d310n.htm
>> and http://www.jsoftware.com/help/dictionary/dicth.htm
>>
>> On Wed, Dec 15, 2010 at 1:39 PM, bill lam <[email protected]> wrote:
>>> In pre-historic J, multi-line explicit definition was defined as array of
>>> boxed strings.
>>> adv2=: 1 : ('';':';'m*y-x')
>>>
>>> Срд, 15 Дек 2010, Graham Parkhouse писал(а):
>>>> How can I write an adverb that returns a noun from 3 noun arguments x, m
>>>> and
>>>> y as a *one liner*?
>>>>
>>>> Just 2 arguments is fine:
>>>> adv1=: 1 : 'm*y'
>>>> 3 adv1 10
>>>> 30
>>>>
>>>> 3 arguments like this doesn't work:
>>>> adv2=: 1 : 'm*y-x'
>>>> 5 (3) adv2 10
>>>> |domain error
>>>> | 5 (3)adv2 10
>>>>
>>>> Giving it a body works:
>>>> adv3=: 1 : 0
>>>> :
>>>> m*y-x
>>>> )
>>>> 5 (3) adv3 10
>>>> 15
>>>>
>>>> Is there a way to do it as one liner?
>>>>
>>>> Regards
>>>>
>>>> Graham Parkhouse
>>>>
>>>>
>>>> ----------------------------------------------------------------------
>>>> For information about J forums see http://www.jsoftware.com/forums.htm
>>>
>>> --
>>> regards,
>>> ====================================================
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>>> gpg --keyserver subkeys.pgp.net --recv-keys 4434BAB3
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>
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